Resistances of both the bulbs are R1=P1V2=252202 R2=P2V2=1002202 Hence R1>R2 When connected in series, the voltages divide in them in the ratio of their resistances. The voltage of 440 V devides in such a way that voltage across 25 w bulb will be more than 220 V. Hence 25 w bulb will fuse.