∮E⋅dA=ε01(ρ×34πr3) E=3ε0ρr Statement 2 is correct ΔPE=(Vsur −Vcent )q=−6ε0qρR2 Statement 1 is incorrect
JEE Main 2012 — Physics Electromagnetism
This question has statement 1 and statement 2 . Of the four choices given after the statements, choose the one that best describes the two statements. An insulating solid sphere of radius R has a uniformly positive charge density ρ. As a result of this uniform charge distribution there is a finite value of electric potential at the centre of the sphere, at the surface of the sphere and also at a point out side the sphere. The electric potential at infinity is zero. Statement 1: When a charge q is taken from the centre to the surface of the sphere, its potential energy changes by 3ε0qp Statement 2: The electric field at a distance r(r<R) from the centre of the sphere is 3ε0ρr
Held on 30 Apr 2012 · Verified 6 Jul 2026.
Statement 1 is true, Statement 2 is true, Statement 2 is not the correct explanation for statement 1.
Statement 1 is true, Statement 2 is false
Statement 1 is false, Statement 2 is true
Statement 1 is true, Statement 2 is the correct explanation for statement 1
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