Equivalent capacitance of n2 number of capacitors each of capacitance C2 in parallel =n2C2 Equivalent capacitance of n1 number of capacitors each of capacitances C1 in series. Capacitance of each is C1=n1C1 According to question, total energy stored in both the combinations are same i.e., 21(n1C1)(4V)2=21(n2C2 b 2∴C2=n1n216C1