Equivalent capacitance of n2 number of capacitors each of capacitance C2 in parallel =n2C2 Equivalent capacitance of n1 number of capacitors each of capacitances C1 in series. Capacitance of each is C1=n1C1 According to question, total energy stored in both the combinations are same i.e., 21(n1C1)(4V)2=21(n2C2 b 2∴C2=n1n216C1
A series combination of n_1 capacitors, each of capacity C_1 is charged by source of potential difference 4 ~V. When another parallel combination of…
JEE Main 2012 — Physics Electromagnetism
A series combination of n1 capacitors, each of capacity C1 is charged by source of potential difference 4 V. When another parallel combination of n2 capacitors each of capacity C2 is charged by a source of potential difference V, it has the same total energy stored in it as the first combination has. The value of C2 in terms of C1 is then
Held on 12 May 2012 · Verified 6 Jul 2026.
Options
- A
16n1n2C1
- B
n1n22C1
- C
2n1n2C1
- D
n1n216C1
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