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Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross sectional area A= 10 ~cm^2 and length =20 ~cm. If one of the…

JEE Main 2008 — Physics Electromagnetism

2008mcqeasy

Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross sectional area A=A=A= 10 cm210 \mathrm{~cm}^210 cm2 and length =20 cm=20 \mathrm{~cm}=20 cm. If one of the solenoids has 300 turns and the other 400 turns, their mutual inductance is (μ0=4π×10−7TmA−1)\left(\mu_0=4 \pi \times 10^{-7} \mathrm{Tm} \mathrm{A}^{-1}\right)(μ0​=4π×10−7TmA−1)

Official previous-year question

Held on 30 Apr 2008 · Verified 6 Jul 2026.

Options

  1. A

    2.4π×10−5H2.4 \pi \times 10^{-5} \mathrm{H}2.4π×10−5H

  2. B

    4.8π×10−4H4.8 \pi \times 10^{-4} \mathrm{H}4.8π×10−4H

  3. C

    4.8π×10−5H4.8 \pi \times 10^{-5} \mathrm{H}4.8π×10−5H

  4. D

    2.4π×10−4H2.4 \pi \times 10^{-4} \mathrm{H}2.4π×10−4H

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