Since there is no deviation in the path of the charged particle, so net force due to presence of electric and magnetic field must be zero ⇒vB=qE⇒B=VE=10104=103 Wb/m2
A particle of charge -16 × 10^-18 coulomb moving with velocity 10 ~ms^-1 along the x-axis enters a region where a magnetic field of induction B is…
JEE Main 2003 — Physics Electromagnetism
A particle of charge −16×10−18 coulomb moving with velocity 10 ms−1 along the x-axis enters a region where a magnetic field of induction B is along the y-axis, and an electric field of magnitude 104 V/m is along the negative z-axis. If the charged particle continues moving along the x-axis, the magnitude of B is
Held on 30 Apr 2003 · Verified 6 Jul 2026.
Options
- A
103 Wb/m2
- B
105 Wb/m2
- C
1016 Wb/m2
- D
10−3 Wb/m2
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