33 codons will be altered if the 901st base is deleted and RNA has only 998 bases instead of 999 bases
Total bases present in RNA = 999
Bases left after deletion of 901st base
In RNA = 999 - 901 = 98
3 codon= 1 amino acid
Therefore 98/3= approx 33
A number of codons present in 98 bases= 33 (Approximately as three codons code for one amino acid).