As per question, we have; θ= ? As K= AΔtQd,where, K= thermal conductivity Q= amount of heat transferred d= distance between two planes A= area of surface, and ΔT= difference in Temp. ΔtΔQ=l385×A×(100∘C−θ)=l50×A×(θ−0∘C)⇒385(100∘C−θ)=50(θ−0∘C)⇒θ=88.5∘C