As per question, we have; θ= ? As K= AΔtQd,where, K= thermal conductivity Q= amount of heat transferred d= distance between two planes A= area of surface, and ΔT= difference in Temp. ΔtΔQ=l385×A×(100∘C−θ)=l50×A×(θ−0∘C)⇒385(100∘C−θ)=50(θ−0∘C)⇒θ=88.5∘C
Two rods one made of copper and other made of steel of the same length and same cross sectional area are joined together. The thermal conductivity of…
NEET UG 2022 — Physics Thermodynamics
Two rods one made of copper and other made of steel of the same length and same cross sectional area are joined together. The thermal conductivity of copper and steel are 385 J s−1 K−1 m−1 and 50 J s−1 m−1 respectively. The free ends of copper and steel are held at 100∘C and 0∘C respectively. The temperature at the junction is, nearly:
Held on 30 Apr 2022 · Verified 9 Jul 2026.
Options
- A
12∘C
- B
50∘C
- C
73∘C
- D
88.5∘C
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