By energy conservation E1+E2=Emix 2n1f1RT1+2n2f2RT2=2(n1×n2)fRTmix ⇒23P1 V1+23P2 V2=23Pmix (V1+V2)23×1×2+23×2×3=23×Pmix (5)∴Pmix =58Pmix =1.6 atm
A container has two chambers of volumes V1=2 litres and V2=3 litres separated by a partition made of a thermal insulator. The chambers contains n1=5 and n2=4 moles of ideal gas at pressures p1=1 atm and p2=2 atm, respectively. When the partition is removed, the mixture attains an equilibrium pressure of :
Held on 30 Apr 2025 · Verified 9 Jul 2026.
1.3 atm
1.6 atm
1.4 atm
1.8 atm
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