Let L= length of each rod Temperature difference =ΔT ∴ Rate of flow of rod (i) is H1= LK1A1ΔT and Rate of flow of rod (2) is H2=LK2A2ΔT from the equation H1⇒⇒=4H2LK1A1ΔTK1A1=4LK2A2ΔT=4K2A2
Two metal rods 1 and 2 of same lengths have same temperature difference between their ends. Their thermal conductivities are K1 and K2 and crosssectional areas A1 and A2 respectively. If the rate of heat conduction in 1 is four times that in 2 , then:
Held on 30 Apr 2013 · Verified 9 Jul 2026.
K1A1=4K2A2
K1A1=2K2A2
4K1A1=K2A2
K1A1=K2A2
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