For all process 1,2 and 3 ∴ Now, ΔU=UB−UA is same ΔU1=ΔU2=ΔU3ΔQ=ΔU+ΔW Now, ΔW= work done by the gas ∴ΔQ1>ΔQ2>ΔQ3
An ideal gas goes from state A to state B via three different processes as indicated in the p−V diagram If Q1,Q2,Q3 indicate the heat absorbed by the gas along the three processes and ΔU1,ΔU2,ΔU3 indicate the change in internal energy along the three processes respectively, then 
Held on 30 Apr 2012 · Verified 9 Jul 2026.
Q1>Q2>Q3 and ΔU1=ΔU2=ΔU3
Q3>Q2>Q1 and ΔU1=ΔU2=ΔU3
Q1=Q2=Q3 and ΔU1>ΔU2>ΔU3
Q3>Q2>Q1 and ΔU1>ΔU2>ΔU3
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In an adiabatic process:
Two gases $A$ and $B$ are filled at the same pressure in separate cylinders with movable pistons of radius $r_A$ and $r_B$, respectively. On supplying an equal amount of heat to both the systems reversibly under constant pressure, the pistons of gas $A$ and $B$ are displaced by 16 cm and 9 cm , respectively. If the change in their internal energy is the same, then the ratio $\frac{r_A}{r_B}$ is equal to
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Three identical heat conducting rods are connected in series as shown in the figure. The rods on the sides have thermal conductivity $2 K$ while that in the middle has thermal conductivity $K$. The left end of the combination is maintained at temperature $3 T$ and the right end at $T$. The rods are thermally insulated from outside. In steady state, temperature at the left junction is $T_1$ and that at the right junction is $T_2$. The ratio $T_1 / T_2$ is 
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