In steady state the amount of heat flowing from one face to the other face in time t is given by Q=lKA(θ1−θ2)t where K is coefficient of thermal conductivity of material of rod ⇒tQ∝lA∝lr2 As the metallic rod is melted and the material is formed into a rod of half the radius V1⇒πr12l1l1=V2=πr22l2=4l2 Now, from Eqs. (i) and (ii) ⇒⇒Q1Q2Q1=l1r12×r22l2=l1r12×(r1/2)24l1=16Q2