C5H12(g)+8O2(9)⟶5CO2(g)+6H2O(e)∴ΔGr=5(ΔGr)CO2+6(ΔGr)H2O−(ΔGr)Pentane =5(−5394.4)+6(−237.2)−(−8.2)=−1972−1423.2+8.2ΔGR=−3387 kJ/moleC55−12H12⟶5C24 For 5 carbon atoms, there is a change of electrons from - 12 to 20 ∴ No. of electrons involved =32e−ΔGr=−3387×103=−32×E∘×96500E∘=1.097V
Standard free energies of formation (in kJ / mol ) at 298 ~K are -237.2,-394.4 and -8.2 for H_2 O(l) CO_2(g) and pentane (g), respectively. The value…
NEET UG 2008 — Chemistry Organic Chemistry
2008mcqmedium
Standard free energies of formation (in kJ/mol ) at 298 K are −237.2,−394.4 and -8.2 for H2O(l)CO2(g) and pentane (g), respectively. The value of Ecell 0 for the pentane-oxygen fuel cell is
Official previous-year question
Held on 30 Apr 2008 · Verified 9 Jul 2026.
Options
- A
1.968 V
- B
2.0968 V
- C
1.0968 V
- D
0.0968 V
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