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In this reaction: … an symmetric centre is generated. The acid obtained would be:

NEET UG 2003 — Chemistry Organic Chemistry

2003mcqeasy

In this reaction: CH3CHO+HCN→CH3CH(OH)CN⟶H.OHCH3CH(OH)COOH\begin{aligned} \mathrm{CH}_3 \mathrm{CHO}+\mathrm{HCN} & \rightarrow \mathrm{CH}_3 \mathrm{CH}(\mathrm{OH}) \mathrm{CN} \\ \stackrel{\mathrm{H} . \mathrm{OH}}{\longrightarrow} & \mathrm{CH}_3 \mathrm{CH}(\mathrm{OH}) \mathrm{COOH} \end{aligned}CH3​CHO+HCN⟶H.OH​​→CH3​CH(OH)CNCH3​CH(OH)COOH​ an symmetric centre is generated. The acid obtained would be:

Official previous-year question

Held on 30 Apr 2003 · Verified 9 Jul 2026.

Options

  1. A

    D-isomer

  2. B

    L-isomer

  3. C

    50%D+50%50 \% \mathrm{D}+50 \%50%D+50% L-isomer

  4. D

    20%D+80% L20 \% \mathrm{D}+80 \% \mathrm{~L}20%D+80% L-isomer

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