The given equation can be written as
x=2acos[1.5+50.5]t+2acos[50.5−1.5]
x=2acos[52t]+2acos[49t]
Here, 2πf1&2πf2=49
f1=2π52,f2=2π49
∴fBat =f1−f2=2π3 Hz
∴TBeat =fBeat 1=32πsec
=2.09sec≈2sec
Two harmonic waves moving in the same direction superimpose to form a wave x=acos(1.5t)cos(50.5t) where t is in seconds. Find the period with which they beat (close to nearest integer)
Held on 7 Apr 2025 · Verified 6 Jul 2026.
6 s
4 s
1 s
2 s
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