$\begin{aligned}
& k=20 \times 10^{-3} \mathrm{mm}^{-1}=20 \mathrm{m}^{-1} \
& w=600 \mathrm{s}^{-1} \
& v=\frac{W}{k}=\frac{600}{20}=30 \mathrm{m} / \mathrm{s}
\end{aligned}andx & tcarrysamesignTherefore\mathrm{v}=-30 \mathrm{~m} / \mathrm{s}$
JEE Main 2025 — Physics Waves & Oscillations
The equation of a transverse wave travelling along a string is y(x,t)=4.0sin[20×10−3x+600t]mm, where x is in mm and t is in second. The velocity of the wave is :
Held on 23 Jan 2025 · Verified 6 Jul 2026.
−60 m/s
−30 m/s
+30 m/s
+60 m/s
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