Given, $\begin{aligned}
& \mathrm{T}=3.14=\frac{2 \pi}{\omega} \
& \omega=2 \mathrm{rad} / \mathrm{s} \
& \mathrm{x}=10 \sin \left(\omega \mathrm{t}+\frac{\pi}{3}\right) \
& \mathrm{v}=\frac{\mathrm{dx}}{\mathrm{dt}}=10 \omega \cos \left(\omega \mathrm{t}+\frac{\pi}{3}\right) \
& \text { at } \mathrm{t}=0 \
& \mathrm{v}=10 \omega \cos \left(\frac{\pi}{3}\right)=10 \times 2 \times \frac{1}{2}[\mathrm{using} \omega=2 \mathrm{rad} / \mathrm{s}] \
& \mathrm{v}=10 \mathrm{~m} / \mathrm{s}
\end{aligned}$
The displacement of a particle executing SHM is given by x=10 sin (w t+ π 3 ) m. The time period of motion is 3.14 ~s. The velocity of the particle…
JEE Main 2024 — Physics Waves & Oscillations
2024integereasy
The displacement of a particle executing SHM is given by x=10sin(wt+3π)m. The time period of motion is 3.14 s. The velocity of the particle at t=0 is ______m/s.
Official previous-year question
Held on 4 Apr 2024 · Verified 6 Jul 2026.
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