Frequency of sonometer wire is given by, f=2L1μT
Therefore, f1=21μ6 f2=21μ54
Hence, f2f1=31
Also it is given that, f2−f1=12
So, f1=6Hz.
A tuning fork resonates with a sonometer wire of length 1m stretched with a tension of 6N. When the tension in the wire is changed to 54N, the same tuning fork produces 12 beats per second with it. The frequency of the tuning fork is _______ Hz.
Held on 1 Feb 2024 · Verified 6 Jul 2026.
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Work through every JEE Main Waves & Oscillations PYQ, year by year.