The distance between two consecutive points… - JEE Main 2023 Physics PYQ

JEE Main 2023 — Physics Waves & Oscillations

2023integereasy

The distance between two consecutive points with phase difference of $60^{\circ}$ in a wave of frequency $500\mathrm{Hz}$ is $6.0m$ . The velocity with which wave is travelling is ______ $\mathrm{km}{s}^{-1}$ .

Official previous-year question

Held on 25 Jan 2023 · Verified 6 Jul 2026.

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Solution

Distance between two consecutive points $60^{\circ}$ out of phase is given by $\Delta x=\frac{\lambda }{2\pi }\Delta \phi$

Putting the values, we have

$6=\frac{\lambda }{2\pi }(\frac{\pi }{3})$

$\Rightarrow \lambda =36m$

Now, velocity of wave is $v=f\lambda =(500\mathrm{Hz})(36m)$

$=18000m{s}^{-1}=18\mathrm{km}{s}^{-1}$

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