μ=0.135gmcm−1=0.0135kgm−1
y=−0.21sin(x+30t)
(x in meter & t in sec)
v=kω=130=30ms−1
v=μT⇒T=v2μ=(30)2(0.0135)
=12.15
=x×10−2N
⇒x=1215
The mass per unit length of a uniform wire is 0.135gcm−1. A transverse wave of the form y=−0.21sin(x+30t) is produced in it, where x is in meter and t is in second. Then, the expected value of tension in the wire is x×10−2N. Value of x is (Round-off to the nearest integer)
Held on 26 Feb 2021 · Verified 6 Jul 2026.
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