Force along the tunnel
F=−(R3GMmr)cosθ
F=−Rgmx (R2GM=g,rcosθ=x)
a=−Rgx
ω2=Rg
T=2πgR
Assume that a tunnel is dug along a chord of the earth, at a perpendicular distance 2R from the earth's centre, where R is the radius of the earth. The wall of the tunnel is frictionless. If a particle is released in this tunnel, it will execute a simple harmonic motion with a time period:
Held on 26 Feb 2021 · Verified 6 Jul 2026.
2π1Rg
2πgR
2πRg
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