x(t)=Asin(ωt+ϕ)
v(t)=Aωcos(ωt+ϕ)
2=Asinϕ ...(1)
2ω=Aωcosϕ ...(2)
From (1) and (2)
tanϕ=1
ϕ=45∘
Putting the value of ϕ in equation (1)
2=A21
A=22
x=2
A particle executes simple harmonic motion represented by displacement function as x(t)=Asin(ωt+ϕ). If the position and velocity of the particle at t=0s are 2cm and 2ωcms−1 respectively, then its amplitude is x2cm where the value of x is
Held on 27 Jul 2021 · Verified 6 Jul 2026.
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