Fundamental frequency: $f_1 = \frac{v}{2L} = \frac{100}{2 \times 1} = 50\,\text{Hz}$
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JEE Main 2020 — Physics Waves & Oscillations
medium
mcq
2020
Official previous-year question
Verified 30 May 2026.
Question
A string of length $1\,\text{m}$ and mass $5\,\text{g}$ is fixed at both ends. The speed of transverse waves on the string is $100\,\text{m/s}$. The fundamental frequency is:
Options
- A
$50\,\text{Hz}$
- B
$100\,\text{Hz}$
- C
$25\,\text{Hz}$
- D
$200\,\text{Hz}$
Solution
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