Torque on the rod about O,
τ=kx.2l×2
Iα=k.2l.θ.2l×2
Iα=k2l2.θ
∴ω2=M12l2k2l2=M6k
f=2π1M6k
Two light identical springs of spring constant k are attached horizontally at the two ends of a uniform horizontal rod AB of length l and mass m. The…
JEE Main 2019 — Physics Waves & Oscillations
2019mcqhard
Two light identical springs of spring constant k are attached horizontally at the two ends of a uniform horizontal rod AB of length l and mass m. The rod is pivoted at its center 'O' and can rotate freely in horizontal plane. The other ends of the two springs are fixed to rigid supports as shown in figure. The rod is gently pushed through a small angle and released. The frequency of resulting oscillation is:
Official previous-year question
Held on 12 Jan 2019 · Verified 6 Jul 2026.
Options
- A
2π1m3k
- B
2π1mk
- C
2π1m6k
- D
2π1m2k
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
JEE Main Waves & Oscillations in other years
Waves & Oscillations 2026Waves & Oscillations 2025Waves & Oscillations 2024Waves & Oscillations 2023Waves & Oscillations 2022Waves & Oscillations 2021Waves & Oscillations 2020Waves & Oscillations 2018Waves & Oscillations 2017Waves & Oscillations 2016Waves & Oscillations 2015Waves & Oscillations 2014
More JEE Main Waves & Oscillations questions
The time period of a simple harmonic oscillator is $T=2 \pi \sqrt{\frac{k}{m}}$. Measured value of mass $(m)$ of the object is 10 g with an accuracy of 10 mg and time for 50 oscillations of the spring is found to be 60 s using a watch of 2 s resolution. Percentage error in determination of spring constant $(k)$ is $\_\_\_\_$ \%.
2026medium
Two waves of same frequency and amplitude travel in opposite directions. The resulting pattern is:
2026easy
A spring-mass system oscillates with angular frequency ω. If the mass is doubled and the spring constant is halved, the new angular frequency is:
2026hard
In an open organ pipe $\nu_{3}$ and $\nu_{6}$ are $3^{\text {rd }}$ and $6^{\text {th }}$ harmonic frequencies, respectively. If $\nu_{6}-\nu_{3}=2200 \mathrm{~Hz}$ then length of the pipe is $\_\_\_\_$ mm . (Take velocity of sound in air is $330 \mathrm{~m} / \mathrm{s}$.)
2026easy
A simple pendulum of string length 30 cm performs 20 oscillations in 10 s. The length of the string required for the pendulum to perform 40 oscillations in the same time duration is $\_\_\_\_$ cm. [Assume that the mass of the pendulum remains same.]
2026easy
Other Physics topics for JEE Main
Keep practicing Waves & Oscillations
Work through every JEE Main Waves & Oscillations PYQ, year by year.