In a simple harmonic motion,
Maximum acceleration, fmax=ω2A
Maximum velocity, vmax=Aω.
vmaxfmax=Aωω2A=ω
ω=10
Displacement in SHM is x=Asin(ωt+4π)
At t=0
5=Asin(4π)
A=52.
Max acceleration = ω2A
=100×52
=5002ms−2
The ratio of maximum acceleration to maximum velocity in a simple harmonic motion is 10 s^-1. At, t=0 the displacement is 5m. What is the maximum…
JEE Main 2017 — Physics Waves & Oscillations
2017mcqmedium
The ratio of maximum acceleration to maximum velocity in a simple harmonic motion is 10s−1. At, t=0 the displacement is 5m. What is the maximum acceleration? The initial phase is 4π .
Official previous-year question
Held on 8 Apr 2017 · Verified 6 Jul 2026.
Options
- A
500ms−2
- B
7502ms−2
- C
750ms−2
- D
5002ms−2
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