Given,
E=2Eo
⇒A=2Ao
Amplitudeofdampedoscillation=A=Aoe−2mbt
⇒2Ao=Aoe−2mbt
2=e2mbt
ln(2)=2mbt=2×0.110−2t=20.1t
2t=10ln(2)=10×21×0.693
t=10×0.693=6.93
t≈7s.
A block of mass 0.1kg is connected to an elastic spring of spring constant 640Nm−1 and oscillates in a damping medium of damping constant 10−2kgs−1 . The system dissipates its energy gradually. The time taken for its mechanical energy of vibration to drop to half of its initial value, is closest to-
Held on 9 Apr 2017 · Verified 6 Jul 2026.
2s
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Work through every JEE Main Waves & Oscillations PYQ, year by year.