Energy of simple harmonic oscillator is constant. ⇒21Mω2A12=21(m+M)ω2A22A22A12=MM+m∴A2A1=MM+m
A mass M, attached to a horizontal spring, executes S.H.M. with amplitude A_1. When the mass M passes through its mean position then a smaller mass m…
JEE Main 2011 — Physics Waves & Oscillations
2011mcqmedium
A mass M, attached to a horizontal spring, executes S.H.M. with amplitude A1. When the mass M passes through its mean position then a smaller mass m is placed over it and both of them move together with amplitude A2. The ratio of (A2A1) is :
Official previous-year question
Held on 30 Apr 2011 · Verified 6 Jul 2026.
Options
- A
MM+m
- B
(M+mM)1/2
- C
(MM+m)1/2
- D
M+mM
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