2ℓn(v)=315,2ℓ(n+1)v=420 Solving 2ℓv=105
A string is stretched between fixed points separated by 75 cm. It is observed to have resonant frequencies of 420 Hz and 315 Hz. There are no other resonant frequencies between these two. Then, the lowest resonant frequency for this string is
Held on 30 Apr 2006 · Verified 6 Jul 2026.
10.5 Hz
105 Hz
1.05 Hz
1050 Hz
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Work through every JEE Main Waves & Oscillations PYQ, year by year.