T=2πKM 
35 T=2πKM+m
Dividing equation (ii) by equation (i), 35=MM+m. Squaring both the sides 925=MM+m=1+Mm⇒Mm=925−1=916
A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T. If the mass is increased by m, the time period becomes 35 T. Then the ratio of Mm is
Held on 30 Apr 2003 · Verified 6 Jul 2026.
53
925
916
35
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