Given: CP=27R, so CV=CP−R=25R
ΔQ=nCVΔT (constant volume)
300=n×25×8.314×30
n=0.48 mol
100n=48
When 300 J of heat given to an ideal gas with Cp=27R its temperature raises from 20∘C to 50∘C keeping its volume constant. If n is the number of moles of the gas, then what is the value of 100n? (R=8.314 J/mol.K)
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