Collision frequency (z)=2πd2NπM8RT
Temp, N are same
Z∝Md2
dA=2dB
MA=4MB
ZBZA=dB2dA2×MAMB=(MAMB)(dBdA)2
=(41)(21)2
ZBZA=21×41=81
⇒ZA=832×108=4×108/s
JEE Main 2026 — Physics Thermodynamics
Consider two boxes containing ideal gases A and B such that their temperatures, pressures and number densities are same. The molecular size of A is half of that of B and mass of molecule A is four times that of B. If the collision frequency in gas B is 32×1018/s then collision frequency in gas A is ____ /s.
Held on 22 Jan 2026 · Verified 6 Jul 2026.
2×108
8×108
4×108
32×108
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