Let [R=3KAℓ]

H=211R100−40 ...(1)
H=R100−TB .....(2)
H=3RTE−40 .....(3)
using (1) and (2)
120=1100−11TA
TB=89°C
using (1) and (3)
TE=73°C
JEE Main 2026 — Physics Thermodynamics
Rods x and y of equal dimensions but of different materials are joined as shown in figure. Temperatures of end points A and F are maintained at 100∘C and 40∘C respectively. Given the thermal conductivity of rodx is three times of that of rody, the temperature at junction points B and E are (close to):

Held on 22 Jan 2026 · Verified 6 Jul 2026.
80∘C and 70∘C respectively
80∘C and 60∘C respectively
60∘C and 45∘C respectively
89∘C and 73∘C respectively
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
10 mole of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from $P_{1}$ to $P_{2}$ is $\alpha$ Joule ($P_{1}=21.7 \mathrm{~Pa}$ and $\left.P_{2}=30 \mathrm{~Pa}, \mathrm{C}_{v}=21 \mathrm{~J} / \mathrm{K}. \mathrm{mol}, R=8.3 \mathrm{~J} / \mathrm{mol}. \mathrm{K}\right)$. The value of $\alpha$ is $\_\_\_\_$. 
Heat is supplied to a diatomic gas at constant pressure. Then the ratio of $\Delta Q : \Delta U : \Delta W$ is _______.
The r.m.s. speed of oxygen molecules at $47^{\circ} \mathrm{C}$ is equal to that of the hydrogen molecules kept at $\_\_\_\_$ ${ }^{\circ} \mathrm{C}$. (Mass of oxygen molecule/mass of hydrogen molecule $=32 / 2$)
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Statement I: Change in internal energy of a system containing $n$ mole of ideal gas can be written as $\Delta U = n C_v (T_f - T_i) = \dfrac{nR}{\gamma - 1}(T_f - T_i)$, where $\gamma = \dfrac{C_p}{C_v}$, $T_i =$ initial temperature, $T_f =$ final temperature. Statement II: Relation between degree of freedom $f$ and $\gamma (= C_p/C_v)$ is $\left(\gamma = 1 + \dfrac{2}{f}\right)$ Choose the correct answer from the options given below
When 300 J of heat given to an ideal gas with $C_{p}=\frac{7}{2} R$ its temperature raises from $20^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$ keeping its volume constant. If n is the number of moles of the gas, then what is the value of $100n$? $(\mathrm{R}=8.314 \mathrm{~J} / \mathrm{mol}. \mathrm{K})$
Work through every JEE Main Thermodynamics PYQ, year by year.