For isothermal expansion of 1 mole diatomic gas from V to 2V at 300 K:
W=RTln2=R(300)ln2
For adiabatic expansion with same volume change and same work output:
W=nCVΔT=CV(Ti−Tf)
For diatomic gas, CV=25R. Setting work equal:
R(300)ln2=25R(300−Tf)
Simplifying:
300ln2=2.5(300−Tf), so 300(0.693)=2.5(300−Tf)
207.9=750−2.5Tf, giving Tf=216.84 K ≈ -56°C.