Using the principle of conservation of internal energy for the mixture of ideal gases:
Umix=U1+U2
(n1+n2)CVTmix=n1CVT1+n2CVT2
Since both gases are monoatomic, their molar heat capacities at constant volume are equal (CV=23R).
(n1+n2)Tmix=n1T1+n2T2
Substituting the given values n1=2, T1=T, n2=6, and T2=2T:
(2+6)Tmix=2(T)+6(2T)
8Tmix=2T+12T
8Tmix=14T
Tmix=814T=47T
Answer: 47T