Given P1=8 bar =8×105 Pa, V1=0.15 m3, and P2=1 bar =105 Pa.
The adiabatic index γ is given by:
γ=cvcp=2R3R=1.5
For an adiabatic process, P1V1γ=P2V2γ.
V2=V1(P2P1)γ1
V2=0.15×(18)1.51=0.15×832=0.15×4=0.6 m3
The work done during the adiabatic expansion is:
W=γ−1P1V1−P2V2
W=1.5−18×105×0.15−1×105×0.6
W=0.51.2×105−0.6×105
W=0.50.6×105=1.2×105 J
W=120 kJ
Answer: 120