$\begin{aligned}
& \Delta T=T_2-T_1=16^{\circ} \mathrm{C} \
& \text { And } T_0=16^{\circ} \mathrm{C} \
& \frac{\Delta T}{t_1}=-k\left(32-16^{\circ}\right)...(i) \
& \frac{\left(24-T_3\right)}{4}=-k\left(\frac{24+T_3}{2}-16\right) ....(ii) \
& \frac{16}{4}=-k(16) \
& \Rightarrow \frac{\left(24-T_3\right)}{4}=-k\left(12+\frac{T_3}{2}-16\right) \
& \Rightarrow \frac{16}{24-T_3}=\frac{16}{T_3} T_2 \
& \Rightarrow \frac{T_3}{2}-4=24-T_3 \
& \Rightarrow \frac{3 T_3}{2}=28 \
& \Rightarrow T_3=\frac{56}{3}{ }^{\circ} \mathrm{C}
\end{aligned}$