$\begin{aligned}
& \Delta T=T_2-T_1=16^{\circ} \mathrm{C} \
& \text { And } T_0=16^{\circ} \mathrm{C} \
& \frac{\Delta T}{t_1}=-k\left(32-16^{\circ}\right)...(i) \
& \frac{\left(24-T_3\right)}{4}=-k\left(\frac{24+T_3}{2}-16\right) ....(ii) \
& \frac{16}{4}=-k(16) \
& \Rightarrow \frac{\left(24-T_3\right)}{4}=-k\left(12+\frac{T_3}{2}-16\right) \
& \Rightarrow \frac{16}{24-T_3}=\frac{16}{T_3} T_2 \
& \Rightarrow \frac{T_3}{2}-4=24-T_3 \
& \Rightarrow \frac{3 T_3}{2}=28 \
& \Rightarrow T_3=\frac{56}{3}{ }^{\circ} \mathrm{C}
\end{aligned}$
The temperature of a body in air falls from 40° C to 24° C in 4 minutes. The temperature of the air is 16° C. The temperature of the body in the next…
JEE Main 2025 — Physics Thermodynamics
The temperature of a body in air falls from 40∘C to 24∘C in 4 minutes. The temperature of the air is 16∘C. The temperature of the body in the next 4 minutes will be:
Held on 24 Jan 2025 · Verified 6 Jul 2026.
Options
- A
314∘C
- B
342∘C
- C
328∘C
- D
356∘C
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