Given that process is isobaric ΔT=50∘C Q in isobaric process =nCpΔT=E1 ΔU in isobaric process =nCvΔT=E2 ∴E2E1=CvCP=γ Given, gas is monoatomic $\begin{aligned}
\therefore \gamma & =1+\frac{2}{\mathrm{f}} \
& =1+\frac{2}{3} \
& =\frac{5}{3}
\end{aligned}Now,asperquestion.\begin{aligned}
& \frac{5}{3}=\frac{x}{9} \
& x=15
\end{aligned}$
The temperature of 1 mole of an ideal monoatomic gas is increased by 50° C at constant pressure. The total heat added and change in internal energy…
JEE Main 2025 — Physics Thermodynamics
The temperature of 1 mole of an ideal monoatomic gas is increased by 50∘C at constant pressure. The total heat added and change in internal energy are E1 and E2, respectively. If E2E1=9x then the value of x is _____
Held on 24 Jan 2025 · Verified 6 Jul 2026.
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