
Area under graph will be magnitude of graph and being counterclockwise graph it would be negative $\begin{aligned}
& \text { Area }=2 P_0 \times V_0+P_0 V_0=3 P_0 V_0 \
& \mathrm{~W}=-3 P_0 V_0
\end{aligned}$
JEE Main 2025 — Physics Thermodynamics

Using the given P−V diagram, the work done by an ideal gas along the path ABCD is :
Held on 23 Jan 2025 · Verified 6 Jul 2026.
3P0 V0
−4P0 V0
−3P0 V0
4P0 V0
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