Q=ΔU+W=0⇒−ΔU=WWD=−nCvΔT⇒∣WD∣=nCvΔT∝T2−T1
∴B&E [Only possibility]
JEE Main 2025 — Physics Thermodynamics
Identify the characteristics of an adiabatic process in a monoatomic gas.
(A) Internal energy is constant.
(B) Work done in the process is equal to the charge in internal energy.
(C) The product of temperature and volume is a constant.
(D) The product of pressure and volume is a constant.
(E) The work done to change the temperature from T1 to T2 is proportional to (T2−T1)
Choose the correct answer from the options given below :
Held on 2 Apr 2025 · Verified 6 Jul 2026.
(A), (C), (D) only
(A), (C), (E) only
(B), (E) only
(B), (D) only
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