
For process A:
logP=γlogV⇒P=Vγ,(γ>1)
PV−γ= Constant
CA=CV+1+γR…(i)
Likewise, for process B→PV−1= Constant
CB=Cv+1+1R
CB=Cv+2R…(ii)
Also, CP=Cv+R…(iii)
By (ii) and (iii), we get
CP>CB>Cv
JEE Main 2024 — Physics Thermodynamics
Two thermodynamical process are shown in the figure. The molar heat capacity for process A and B are CA and CB. The molar heat capacity at constant pressure and constant volume are represented by CP and CV, respectively. Choose the correct statement.

Held on 30 Jan 2024 · Verified 6 Jul 2026.
CP>CB>CV
CA=0 and CB=∞
CP>CV>CA=CB
CA>CP>CV
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