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The temperature of a gas having 2.0× 10^25 molecules per cubic meter at 1.38 atm (Given, k=1.38× 10^-23JK^-1) is :

JEE Main 2024 — Physics Thermodynamics

2024mcqeasy

The temperature of a gas having 2.0×10252.0\times {10}^{25}2.0×1025 molecules per cubic meter at 1.38atm1.38\mathrm{atm}1.38atm (Given, k=1.38×10−23JK−1)k=1.38\times {10}^{-23}J{K}^{-1})k=1.38×10−23JK−1) is :

Official previous-year question

Held on 29 Jan 2024 · Verified 6 Jul 2026.

Options

  1. A

    500K500K500K

  2. B

    200K200K200K

  3. C

    100K100K100K

  4. D

    300K300K300K

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