Given R0=8Ω,R100=10Ω ∴R100=R0(1+αΔT)
Also, R400=R0(1+αΔT1) $\begin{aligned}
& \therefore 10=8(1+\alpha \times 100) \Rightarrow 100 \alpha=\frac{1}{4} \
& \therefore \mathrm{R}_{400}=8(1+400 \alpha)=8(1+1)=16 \Omega
\end{aligned}$
The resistances of the platinum wire of a platinum resistance thermometer at the ice point and steam point are 8Ω and 10Ω respectively. After inserting in a hot bath of temperature 400∘C, the resistance of platinum wire is :
Held on 4 Apr 2024 · Verified 6 Jul 2026.
10Ω
8Ω
16Ω
2Ω
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