1st law of thermodynamics $\begin{aligned}
& \Delta \mathrm{Q}=\Delta \mathrm{U}+\mathrm{W} \
& \Rightarrow+48=\mathrm{nC}_{\mathrm{v}} \Delta \mathrm{T}+\mathrm{W} \
& \Rightarrow 48=(1)\left(\frac{3 \mathrm{R}}{2}\right)(2)+\mathrm{W} \
& \Rightarrow \mathrm{W}=48-3 \times \mathrm{R} \
& \Rightarrow \mathrm{W}=48-3 \times(8.3) \
& \Rightarrow \mathrm{W}=23.1 \text { Joule }
\end{aligned}$
A total of 48 ~J heat is given to one mole of helium kept in a cylinder. The temperature of helium increases by 2° C. The work done by the gas is:…
JEE Main 2024 — Physics Thermodynamics
A total of 48 J heat is given to one mole of helium kept in a cylinder. The temperature of helium increases by 2∘C. The work done by the gas is: Given, R=8.3 J K−1 mol−1.
Held on 6 Apr 2024 · Verified 6 Jul 2026.
Options
- A
24.9 J
- B
72.9 J
- C
48 J
- D
23.1 J
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
JEE Main Thermodynamics in other years
More JEE Main Thermodynamics questions
The temperature of a metal strip having coefficient of linear expansion $\alpha$ is increased from $T_1$ to $T_2$ resulting in increase of its length by $\Delta L_1$. The temperature is further increased from $T_2$ to $T_3$ such that the increase in its length is $\Delta L_2$. Given $T_3+T_1=2T_2$ and $T_2-T_1=\Delta T$, the value of $\Delta L_2$ is ______.
The mean free path of a molecule of diameter $5 \times 10^{-10} \mathrm{~m}$ at the temperature $41^{\circ} \mathrm{C}$ and pressure $1.38 \times 10^{5} \mathrm{~Pa}$, is given as $\_\_\_\_$ m. (Given $k_{B}=1.38 \times 10^{-23} \mathrm{~J} / \mathrm{K}$).
Two closed vessels of same volume are joined through a narrow tube and both vessels are filled with air of pressure $90$ kPa and temperature $400$ K. Keeping the temperature of one vessel constant at $400$ K the second vessel temperature is raised to $500$ K. The final pressure in the vessels is _______ kPa.
Heat is supplied to a diatomic gas at constant pressure. Then the ratio of $\Delta Q : \Delta U : \Delta W$ is _______.
An ideal gas undergoes a process maintaining relation between pressure $(P)$ and volume $(V)$ as $P = P_o\left(1 + \left(\dfrac{V_o}{V}\right)^2\right)^{-1}$, where $P_o$ and $V_o$ are constants. If two samples $A$ and $B$ (two moles each) with initial volumes $V_o$ and $3V_o$ respectively undergo above mentioned process and attain same pressure, then the difference at the temperatures of these samples, $T_B - T_A$ is _____. ($R = $ gas constant)
Other Physics topics for JEE Main
Keep practicing Thermodynamics
Work through every JEE Main Thermodynamics PYQ, year by year.