TVγ−1= constant ⇒T(V)23−1=Tf(2 V)23−1⇒TV21=Tf(2)21( V)21⇒Tf=(2T) Now, W.D. =1−γnRΔT=1−231⋅R[2T−T]⇒ W.D. =2RT[1−21]⇒ W.D. =RT[2−2]
A sample of 1 mole gas at temperature T is adiabatically expanded to double its volume. If adiabatic constant for the gas is γ= 3 2, then the work…
JEE Main 2024 — Physics Thermodynamics
A sample of 1 mole gas at temperature T is adiabatically expanded to double its volume. If adiabatic constant for the gas is γ=23, then the work done by the gas in the process is:
Held on 9 Apr 2024 · Verified 6 Jul 2026.
Options
- A
TR[2−2]
- B
RT[2+2]
- C
RT [2−2]
- D
RT[2+2]
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