Given here, ΔQ=0
From first law of thermodynamics, ΔQ=ΔU+W, where, ΔU is change in internal energy and W is work done.
We have, ΔU=−W
W=AreaunderP−Vcurve=∫PdV
Here, volume decreases, hence work done by system will be negative.
ΔU=−W=30×103×150×10−6
=4500×10−3
=4.5J
