
Let Δl be the decease in length of rod due to decease in temperature
Then, Δl=lαΔT, here, coefficient of linear expansion is α=2×10−5K−1 and ΔT=(483−433)K=50K
Thus, Δl=1×2×10−5×50=10−3m
Young's modulus is stated as Y=lΔlAF, here, F=Mg.
So, 2×1011=3×10−6×10−3Mg×1
⇒Mg=2×1011×3×10−9=6×10−2
Thus, M=60kg