Expansion of hole will be similar to that of an imaginary disc.
Let diameter be d0 at 27∘C and d′ at 177∘C. Therefore, we can write
d′=d0(1+αΔT)
Therefore, change in diameter will be
⇒d′−d0=(5)×(1.6×10−5)×(177−27)
=12×10−3cm
Hence, required value of d=12.