As per working of thermometers, UFP−LFPX−LFP=constant.
Therefore, we can write
95∘−5∘41∘−5∘=100∘−0∘C−0∘
⇒C=9036×100=40∘C=40+273K=313K
A faulty thermometer reads 5∘C in melting ice and 95∘C in steam. The correct temperature on absolute scale will be ______ K when the faulty thermometer reads 41∘C.
Held on 30 Jan 2023 · Verified 6 Jul 2026.
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