Given here, P1=270kPa,T1=27+273=300K,T2=36+273=309K
Ideal gas equation is given by PV=nRT.
Considering isochoric process, i.e., constant volume so P∝T
Thus, T1P1=T2P2
⇒P2=T1P1×T2=300270×(309)
=278kPa
JEE Main 2023 — Physics Thermodynamics
A bicycle tyre is filled with air having pressure of 270kPa at 27∘C. The approximate pressure of the air in the tyre when the temperature increases to 36∘C is
Held on 29 Jan 2023 · Verified 6 Jul 2026.
270kPa
262kPa
278kPa
360kPa
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