Molecular specific heat at constant volume in terms of degrees of freedom is given by CV=2fR
Molecular specific heat of mixture at constant volume is CV/mix=n1+n2n1CV1+n2CV2
=1+31×23R+3×25R
=49R=4α2R
⇒α=3
One mole of a monoatomic gas is mixed with three moles of a diatomic gas. The molecular specific heat of mixture at constant volume is 4α2RJmolK−1; then the value of α will be _____ . (Assume that the given diatomic gas has no vibrational mode.)
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