T₁ = 400 K, T₂ = 300 K. η = 1 - T₂/T₁ = 1 - 300/400 = 25%
Back to JEE Main 2022 Thermodynamics
JEE Main 2022 — Physics Thermodynamics
medium
mcq
2022
Official previous-year question
Verified 30 May 2026.
Question
The efficiency of a Carnot engine working between 127°C and 27°C is:
Options
- A20%
- B25%
- C50%
- D75%
Solution
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